(PHP 5 >= 5.2.0)
pg_field_table — Returns the name or oid of the tables field
說明
mixed pg_field_table ( resource$result
, int $field_number
[, bool $oid_only
= false
] )
pg_field_table() returns the name of the table that field
belongs to, or the table's oid if oid_only
is TRUE
.
參數
result
PostgreSQL query result resource, returned by pg_query(), pg_query_params() or pg_execute() (among others).
field_number
Field number, starting from 0.
oid_only
By default the tables name that field belongs to is returned but
if oid_only
is set to TRUE
, then the
oid will instead be returned.
返回值
On success either the fields table name or oid. Or, FALSE
on failure.
范例
Example #1 Getting table information about a field
<?php
$dbconn = pg_connect("dbname=publisher") or die("Could not connect");
$res = pg_query($dbconn, "SELECT bar FROM foo");
echo pg_field_table($res, 0);
echo pg_field_table($res, 0, true);
$res = pg_query($dbconn, "SELECT version()");
var_dump(pg_field_table($res, 0));
?>
以上例程的輸出類似于:
foo 14379580 bool(false)
注釋
Note:
Returning the oid is much faster than returning the table name because fetching the table name requires a query to the database system table.
參見
pg_field_name() - 返回字段的名字 pg_field_type() - 返回相應字段的類型名稱